我想为当前时间逻辑编写测试用例。这是我的 Java 课程。
public static void main(String []args){
final ZonedDateTime passedDate = ZonedDateTime.parse("2021-03-09T05:00:00.000Z");
if(isAgentConfirmationRequired()) {
// Some codes...
}
}
private static boolean isAgentConfirmationRequired(final ZonedDateTime appointment)
{
final ZonedDateTime appointmentTime = appointment.withZoneSameInstant(ZoneId.of("Europe/Paris"));
final ZonedDateTime todayTime = ZonedDateTime.now(ZoneId.of("Europe/Paris"));
final DayOfWeek dayOfToday = todayTime.toLocalDate().getDayOfWeek();
if (dayOfToday == DayOfWeek.SATURDAY || dayOfToday == DayOfWeek.SUNDAY) {
// For weekend user can't update appointment for next business day.
return appointmentTime.toLocalDate().isBefore(getNextAvailableBusinessDayForBooking(todayTime));
}
return todayTime.toLocalTime().isAfter(LocalTime.of(THREE_PM, 0)) && appointmentTime.toLocalDate().isBefore(getNextAvailableBusinessDayForBooking(todayTime));
}
private LocalDate getNextAvailableBusinessDayForBooking(final ZonedDateTime today)
{
long nextAvailableDayCount = 2;
final DayOfWeek day = today.toLocalDate().plusDays(nextAvailableDayCount).getDayOfWeek();
if (day == DayOfWeek.SATURDAY || day == DayOfWeek.SUNDAY) {
nextAvailableDayCount += 2;
} else if (day == DayOfWeek.MONDAY) {
nextAvailableDayCount += 1;
}
return today.toLocalDate().plusDays(nextAvailableDayCount);
}
如果当前时间不在下午 3 点之后，则代码覆盖率低于 50%。有人可以建议我如何在测试用例中模拟 currentDateTime，所以当涉及到“ZonedDateTime.now(ZoneId.of("Europe/Paris"))”时，它将使用模拟的日期时间？
测试应该在何时何地执行是独立的。为了使它们独立于当前环境时间，您应该考虑创建一个提供当前时间的接口。
例如
public interface TimeProvider {
ZonedDateTime getCurrentZonedDateTime()
}
对于生产代码，您有一个返回当前时间的简单实现，对于测试，您可以模拟其行为，例如使用 Mockito。
var timeProvider = Mockito.mock(TimeProvicer.class)
var testTime = ...
Mockito.when(timeprovider.getCurrentZonedDateTime()).thenReturn( testTime )
myProgram.setTimeProvider(timeProvider)
现在测试将始终返回相同的结果。
也许您需要确保除了默认的 ZonedDateTime.now() 实现之外，您不会调用 TimeProvider（或任何其他返回当前时间的方法）。